**Fractions and Decimals Class 7 Ex. 2.5;**

**New Ncert Solution for Class 7 Maths Chapter 2 Fractions and Decimals Free Solution;**

**Exercise 2.5**

**Question 1 :- Find:**

**(i) 0.4 ÷ 2**

**(ii) 0.35 ÷ 5**

**(iii) 2.48 ÷ 4**

**(iv) 65.4 ÷ 6**

**(v) 651.2 ÷ 4**

**(vi) 14.49 ÷ 7**

**(vii) 3.96 ÷ 4**

**(viii) 0.80 ÷ 5**

**Solution 1:-**

**Question 2 :- Find:**

**(i) 4.8 ÷ 10**

**(ii) 52.5 ÷ 10**

**(iii) 0.7 ÷ 10**

**(iv) 33.1 ÷ 10**

**(v) 272.23 ÷ 10**

**(vi) 0.56 ÷ 10**

**(vii) 3.97 ÷10**

**Solution 2:-**

(i) 4.8 ÷ 10 = 0.48 [Shifting the decimal point to the left by one place)

(ii) 52.5 ÷ 10 = 5.25 [Shifting the decimal point to the left by one place)

(iii) 0.7 ÷ 10 = 0.07 [Shifting the decimal point to the left by one place)

(iv) 33.1 ÷ 10 = 3.31 [Shifting the decimal point to the left by one place)

(v) 272.23 ÷ 10 = 27.223 [Shifting the decimal point to the left by one place)

(vi) 0.56 ÷ 10 = 0.056 [Shifting the decimal point to the left by one place)

(vii) 3.97 ÷ 10 = 0.397 [Shifting the decimal point to the left by one place)

**Question 3 :- Find:**

**(i) 2.7 ÷ 100**

**(ii) 0.3 ÷ 100**

**(iii) 0.78 ÷ 100**

**(iv) 432.6 ÷ 100**

**(v) 23.6 ÷ 100**

**(vi) 98.53 ÷ 100**

**Solution 3:-**

(i) 2.7 ÷ 100 = 0.027 [Shifting the decimal point to the left by 2 places)

(ii) 0.3 ÷ 100 = 0.003 [Shifting the decimal point to the left by 2 places)

(iii) 0.78 ÷ 100 = 0.0078 [Shifting the decimal point to the left by 2 places)

(iv) 432.6 ÷ 100 = 4.326 [Shifting the decimal point to the left by 2 places)

(v) 23.6 ÷ 100 = 0.236 [Shifting the decimal point to the left by 2 places)

(vi) 98.53 ÷ 100 = 0.9853 [Shifting the decimal point to the left by 2 places)

**Question 4 :- Find :**

**(i) 7.9 ÷ 1000**

**(ii) 26.3 ÷ 1000**

**(iii) 38.53 ÷ 1000**

**(iv) 128.9 ÷ 1000**

**(v) 0.5 ÷ 1000**

**Solution 4:- **

(i) 7.9 ÷ 1000 = 0.0079 [Shifting the decimal point to the left by 3 places)

(ii) 26.3 ÷ 1000 = 0.0263 [Shifting the decimal point to the left by 3 places)

(iii) 38.53 ÷ 1000 = 0.03853 [Shifting the decimal point to the left by 3 places)

(iv) 128.9 ÷ 1000 = 0.1289 [Shifting the decimal point to the left by 3 places)

(v) 0.5 ÷ 1000 = 0.0005 [Shifting the decimal point to the left by 3 places)

**Question 5 :- Find :**

**(i) 7 ÷ 3.5**

**(ii) 36 ÷ 0 .2**

**(iii) 3.25 ÷ 0.5**

**(iv) 30.94 ÷ 0.7**

**(v) 0.5 ÷ 0.25**

**(vi) 7.75 ÷ 0.25**

**(vii) 76.5 ÷ 0.15**

**(viii) 37.8 ÷ 1.4**

**(ix) 2.73 ÷ 1.3**

**Solution 5:-**

**Question 6 :- A vehicle covers a distance, 43.2-km in 2.4-litres of Petrol. How-much distance will it cover in one-litre of petrol ???**

**Solution 6:-**

Since, 2.4-litres of petrol required to cover distance = 43.2-km;

So, 1-litre of petrol required to cover distance = 43.2/2.4 = 18-km;

Hence, the required distance = 18 km

**Chapter-2, Fractions and Decimals Class-7 Exercise-2.5 for Free**