**Knowing Our Numbers Chapter 1 Ncert Class 6 Math Solution.**

Knowing Our Numbers Exercise 1.1

Knowing Our Numbers Exercise 1.3

**Exercise 1.2**

**Question 1 :-** A book exhibition was held for four days in a school. The number of tickets sold at the counter on the first, second, third and final day was respectively 1094, 1812, 2050 and 2751. Find the total number of tickets sold on all the four days ?

**Solution 1:-**

Number of tickets sold on the first day = 1094

Number of tickets sold on the second day = 1812

Number of tickets sold on the third day = 2050

Number of tickets sold on the final day = 2751

Total number of tickets sold on all the four days = 1094 + 1812 + 2050 + 2751 = **7,707 tickets.**

**Question 2 :- **Shekhar is a famous cricket player. He has so far scored 6980 runs in test matches. He wishes to complete 10,000 runs. How many more runs does he need?

**Solution 2:-**

Shekhar has so far scored = 6980 runs

He wishes to complete =10,000 runs.

So, The total number of runs needed by him = 10,000 – 6980 = **3020 runs.**

**Question 3 :-**In an election, the successful candidate registered 5,77,500 votes and his nearest rival secured 3,48,700 votes. By what margin did the successful candidate win the election?

**Solution 3:-**

Number of votes secured by the successful candidate = 5,77,500

Number of votes secured by his nearest rival = 3,48,700

Therefore, margin of votes to win the election = 5,77,500 – 3,48,700= **2,28,800 votes.**

**Question 4 :-**Kirti bookstore sold books worth ₹2,85,891 in the first week of June and books worth ₹4,00,768 in the second week of the month. How much was the sale for the two weeks together? In which week was the sale greater and by how much?

**Solution 4:-**

Books sold in first week of June worth = ₹2,85,891

Books sold in second week of the month worth = ₹4,00,768

Therefore, total sale of books in the two weeks together = ₹2,85,891 + ₹4,00,768= **₹6,86,659**

The **second week** of the month saw a rise in book sales.

Difference of the sale of books = ₹4,00,768 – ₹2,85,891= **₹1,14,877**

The sale of books increased by **₹1,14,877** in the second week of June as a result.

**Question 5 :- **Find the difference between the greatest and the least 5-digit number that can be written using the digits 6, 2, 7, 4, 3 each only once.

**Solution 5:-**

The digits are 6, 2, 7, 4, 3

Greatest number = 76432

Least number = 23467

So the differences are = 76432 – 23467 = **52,965.**

**Question 6:- **A machine, on an average, manufactures 2,825 screws a day. How many screws did it produce in the month of January, 2006?

**Solution6:-**

Number of screws manufactured in a day = 2,825.

the quantity of screws produced in January = 31 x 2825 = **87,575 screws.**

**Question 7 :- **A merchant had ₹78,592 with her. She placed an order for purchasing 40 radio sets at ₹1200 each. How much money will remain with her after the purchase?

**Solution 7:-**

The total amount of money = ₹78,592

Number of radio sets = 40

Price of one radio set = ₹1200

Therefore, cost of 40 radio sets = ₹1200 x 40 = ₹48,000

The remaining money = ₹78,592 – ₹48000 = **₹30,592**

**Question 8 :- **A student multiplied 7236 by 65 instead of multiplying by 56. By how much was his answer greater than the correct answer?

**Solution 8 :-**

The difference between the two multiplications are = (65 – 56) x 7236

= 9 x 7236 = **65124**

**Question 9 :- **To stitch a shirt, 2 m 15 cm cloth is needed. Out of 40 m cloth, how many shirts can be stitched and how much cloth will remain?

**Solution 9 :-**

Total length of the cloth = 40 m

= 40 x 100 cm = 4000 cm.

Needs for stitch a shirt = 2 m 15 cm

= 2 x 100 + 15 cm = 215 cm

Therefore, number of shirts stitched = 4000/215

So, the number of shirts stitched = **18 shirts.**

the remaining cloth = 130 cm = **1 m 30 cm.**

**Question 10 :- **Medicine is packed in boxes, each weighing 4 kg 500 g. How many such boxes can be loaded in a van which cannot carry beyond 800 kg?

**Solution 10 :-**

One box’s weight = 4 kg 500 g

= 4 x 1000 + 500 = 4500 g

800 kg = 800 x 1000 = 800000 g

**177 boxes** may so only be loaded into the van.

**Question 11 :- **The distance between the school and a student’s house is 1 km 875 m. Everyday she walks both ways. Find the total distance covered by her in six days.

**Solution 11:-**

the separation between the home and the school = 1 km 875 m

= (1000 + 875) m = 1875 m.

The distance travelled by the student in both ways = 2 x 1875 = 3750 m

The distance travelled in 6 days = 3750 m x 6

= 22500 m = 22 km 500 m.

Consequently, the total distance traveled in six days= **22 km 500 m.**

**Question 12 :- **A vessel has 4 litres and 500 ml of curd. In how many glasses, each of 25 ml capacity, can it be filled?

**Solution 12:-**

Quantity of curd in a vessel = 4 litres 500 m

= (4 x 1000 + 500) ml = 4500 ml.

Capacity of 1 glass = 25 ml

Therefore number of glasses = 4500/25= **180 glasses.**

**Ncert FREE SOLUTION for Class 6 Maths Chapter 1 Knowing Our Numbers.**

knowing our numbers

knowing our numbers

knowing our numbers

knowing our numbers

knowing our numbers

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