**Mensuratio****n Class 6 Ex. 10.2**

**Mensuration, Ncert Class 6, Chapter 10, Exercise 10.2 Math Free Solution.**

**Exercise 10.2**

**Question 1 :- Find the areas of the following figures by counting square:**

**Solution 1 :-**

(a) Number of full squares = 9

Area of 1 square = 1 square unit;

Since, the area of 9 squares = 9 x 1 square unit = 9 square units;

So, the area of the portion covered by 9 squares = 9 square units.

(b) Number of full squares = 5

Area of 1 square = 1 square unit;

Since, the area of 5 squares = 5 x 1 square unit = 5 square units;

So, the area of the portion covered by 5 squares = 5 square units.

(c) Number of full squares = 2

Number of half squares = 4

Since, the area of the covered figure = 2 x 1 + 4 x (1/2) = 2 + 2 = 4 square units.

So, the area of the portion covered = 4 square units.

(d) Number of full squares = 8

Area of 1 square = 1 square unit;

Since, the area of 8 squares = 8 x 1 square unit = 8 square units;

So, the area of the portion covered by 8 squares = 8 square units.

(e) Number of full squares = 10

Area of 1 square = 1 square unit;

Since, the area of 10 squares = 10 x 1 square unit = 10 square units;

So, the area of the portion covered by 10 squares = 10 square units.

(f) Number of full squares = 2

Number of half squares = 4

Since, the area of the covered figure = 2 x 1 + 4 x (1/2) = 2 + 2 = 4 square units.

So, the area of the portion covered = 4 square units.

(g) Number of full squares = 4

Number of half squares = 4

Since, the area of the covered figure = 4 x 1 + 4 x (1/2) = 4 + 2 = 6 square units.

So, the area of the portion covered = 6 square units.

(h) Number of full squares = 5

Area of 1 square = 1 square unit;

Since, the area of 5 squares = 5 x 1 square unit = 5 square units;

So, the area of the portion covered by 5 squares = 5 square units.

(i) Number of full squares = 9

Area of 1 square = 1 square unit;

Since, the area of 9 squares = 9 x 1 square unit = 9 square units;

So, the area of the portion covered by 9 squares = 9 square units.

(j) Number of full squares = 2

Number of half squares = 4

Since, the area of the covered figure = 2 x 1 + 4 x (1/2) = 2 + 2 = 4 square units.

So, the area of the portion covered = 4 square units.

(k) Number of full squares = 4

Number of half squares = 2

Since, the area of the covered figure = 4 x 1 + 2 x (1/2) = 4 + 1 = 5 square units.

So, the area of the portion covered = 5 square units.

(l) Number of full squares = 4

Number of squares more than half = 3

Number of half squares = 2

So, the area of the covered figure = [4 x 1 + 3 x 1 + 2 x (1/2)] square units

= (4 + 3 + 1) square units = 8 square units.

(m) Number of full squares = 6

Number of squares more than half = 8

So, the area of the covered figure = [6 x 1 + 8 x 1 ] square units

= (6 + 8) square units = 14 square units.

(n) Number of full squares = 9

Number of squares more than half = 9

So, the area of the covered figure = [9x 1 + 9 x 1 ] square units

= (9 + 9) square units = 18 square units.

**Chapter 10 Mensuration Class 6 Exercise. 10.2 for Free**